a) [tex]\dfrac{7}{8}+{\dfrac{^{4)}1}{\ 2}} = \dfrac{7}{8}+\dfrac{4}{8}=\dfrac{7+4}{8}=\dfrac{11}{8} =1\dfrac{3}{8}[/tex]
b) [tex]\dfrac{^{2)}1}{\ 2}+\dfrac{1}{4} = \dfrac{2}{4}+\dfrac{1}{4}=\dfrac{2+1}{4}=\dfrac{3}{4}[/tex]
c) [tex]\dfrac{3}{10}+\dfrac{^{2)}2} {\ 5}=\dfrac{3}{10}+\dfrac{4}{10}=\dfrac{3+4}{10}= \dfrac{7}{10}[/tex]
d) [tex]\dfrac{1}{6} + \dfrac{^{2)}2}{\ 3} =\dfrac{1}{6} + \dfrac{4}{6} =\dfrac{1+4}{6} =\dfrac{5}{6}[/tex]
e) [tex]\dfrac{^{4)}3}{\ 5} + \dfrac{1}{20} =\dfrac{12}{20} + \dfrac{1}{20} = \dfrac{12+1}{20} =\dfrac{13}{20}[/tex]
