[tex]\displaystyle a) \\
\texttt{Aplicam reciproca teoremei lui Thales: } \\
\texttt{Verificam daca segmentele sunt proportionale: } \\ \\
\frac{AD}{AB} = \frac{AE}{AC} \\ \\
\frac{4}{12} = \frac{3}{9} = \frac{1}{3} \\ \\
\Longrightarrow ~~ DE \parallel BC\\ \\
b)\\
\texttt{Aplicam teorema lui Thales: } \\ \\
\frac{DE}{BC} = \frac{1}{3} ~~~~\Longrightarrow ~~ DE = \frac{BC}{3}= \frac{12}{3}= 4~cm[/tex]