[tex]S+ H_{2} -\ \textgreater \ H_{2}S
2g H_{2}........34 g H_{2}S
xg H_{2}........6.8 g H_{2}S
[/tex]
x=(2*6.8)/34=0.4 g H2 utilizat in prima reactie =>12-0.4=11.6 g H2 exces
H2+ Cl2-> 2 HCl
2g H2............71 g HCl
y g H2............28.4 g HCl
y= (2*28.4)/71=0.8 g =>11.6-0.8=10.8 H2 exces
nr moli:10.8/2=5.4 moli H2
V=5.4*22.4=120.96 l H2
