Răspuns :
A = (1;4;9) C (1)
C (4)
C (9)
C (1;4)
C (4:9)
C (1;9)
C (1;4;9)
C multime vida adica 0 taiat
C= contine
C (4)
C (9)
C (1;4)
C (4:9)
C (1;9)
C (1;4;9)
C multime vida adica 0 taiat
C= contine