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(1+2a-a+ax0+ax1+a):10=10

Răspuns :

(1+2a-a+ax0+ax1+a):10=10
(1+a+0+a+a):10=10
1+3a=10 x 10
3a=100-1
a=99:3
a=33

3a/10+1/10=0
(3a+1)/10=10
[10(3a+1)]/10=10*10
3a+1=10*10=>3a+1=100=>3a=100-1=>3a=99=>a=99/3=>a=33