Răspuns :
[1141-(65+72+80)]÷3=[1141-217]÷3=924÷3=308
primul numar 308+65=373
al doilea numar 308+72=380
al treilea numar 308+80=388
primul numar 308+65=373
al doilea numar 308+72=380
al treilea numar 308+80=388
a+b+c=1141
a+65+b+72+c+80=1141
1141-(65+72+80)=1141-217=924
924:3=308
308+65=373
308+72=380
308+80=388
a+65+b+72+c+80=1141
1141-(65+72+80)=1141-217=924
924:3=308
308+65=373
308+72=380
308+80=388