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a fost răspuns

 AJUTATI-MA !!sa se descompuna in factori : x²+7x+12=
x²-6x+8=
x²+11x²+18=
x²-14x+48=

Răspuns :

Renatemambouko
x²+7x+12= x²+4x+3x+12=x(x+4)+(3(x+4)=(x+4)(x+3)

x²-6x+8=x²-2x-4x+8=x(x-2)-4(x-2)=(x-2)(x-4)

x²+11x²+18=x²+9x+2x+18=x(x+9)+2(x+9)=(x+9)(x+2)

x²-14x+48= x²-6x-8x+48=x(x-6)-8(x-6)=(x-6)(x-8)

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