Calculez nr.kmoli carbonat da calciu din masa data, stiind masa lui molara:
M=(4OgCa +12gC+4X16g))/mol= 100g/mol= 1ookg/kmol
n sau niu = m/M =. 5ookg/100kg/kmol=5kmol
1kmol 1kmol
Ca Co3 + 2HCl = CaCl2 +CO2 +H20
5kmol 5kmol
n sau niu = 5 kmol carbonat de calciu
m= niuxM==> 5kmolx44kg/kmol==220kg= 220000g
V =niuxV,m===> 5kmolx22,4m³==112m³=112000 l