Răspuns :
Suma lui Gauss:
[tex]1+2+3+...+n= \frac{n(n+1)}{2} [/tex]
Aplici formula: 1+2+...+223=223(223+1)/2=24976
[tex]1+2+3+...+n= \frac{n(n+1)}{2} [/tex]
Aplici formula: 1+2+...+223=223(223+1)/2=24976
pai 1+2+3+.......+223=? aplicam teorema n*(n+1):2
=1+2+3 +....+223
=223*(223+1):2
=223*224:2
=223*112
=24976
sper ca te-am ajutat!
coroana???
=1+2+3 +....+223
=223*(223+1):2
=223*224:2
=223*112
=24976
sper ca te-am ajutat!
coroana???