Răspuns :
[5x5²+15²⁰:(5²⁰x3¹⁸)]:2=
[5¹⁺²+(3x5)²⁰:5²⁰x3¹⁸]:2=
[5³+3²⁰x5²⁰:5²⁰x3¹⁸]:2=
(125+3²⁰⁻¹⁸x5²⁰⁻²⁰):2=
(125+3²x5⁰):2=
(125+9x1):2=134:2=67
[5¹⁺²+(3x5)²⁰:5²⁰x3¹⁸]:2=
[5³+3²⁰x5²⁰:5²⁰x3¹⁸]:2=
(125+3²⁰⁻¹⁸x5²⁰⁻²⁰):2=
(125+3²x5⁰):2=
(125+9x1):2=134:2=67
Calculam paranteza rotunda :
[tex]15^{20}:(5^{20}\cdot3^{18}) = \dfrac{15^{20}}{5^2\cdot5^{18}\cdot 3^{18}} =\dfrac{15^2\cdot15^{18}}{5^2\cdot15^{18}} = \left(\dfrac{15}{5}\right)^2=3^2=9[/tex]
Acum exercitiul devine:
[tex](5\cdot5^2+9):2 =134:2=67[/tex]
[tex]15^{20}:(5^{20}\cdot3^{18}) = \dfrac{15^{20}}{5^2\cdot5^{18}\cdot 3^{18}} =\dfrac{15^2\cdot15^{18}}{5^2\cdot15^{18}} = \left(\dfrac{15}{5}\right)^2=3^2=9[/tex]
Acum exercitiul devine:
[tex](5\cdot5^2+9):2 =134:2=67[/tex]
