Răspuns :
a+b+c=198
2a=124 ⇒ a = 124/2 ⇒ a = 62
b=3c
inlocuim in prima ecuatie si avem:
62+3c+c=198
4c=198-62
4c=136
c=136/4
c=34
b = 3c ⇒
b = 3*34
b = 102
proba
62+102+34=198
2a=124 ⇒ a = 124/2 ⇒ a = 62
b=3c
inlocuim in prima ecuatie si avem:
62+3c+c=198
4c=198-62
4c=136
c=136/4
c=34
b = 3c ⇒
b = 3*34
b = 102
proba
62+102+34=198
2a=124
a=62
a+b+c=198
62+b+c=198
b+c=136
1) Metoda figurativa
b |..............|..............|............|
c |..............|
4 segmente=136⇒c=34⇒b=102
2) Metoda algebrica
b:c=3⇒b=3c
3c+c=136
4c=136
c=34
b=102
a=62
a+b+c=198
62+b+c=198
b+c=136
1) Metoda figurativa
b |..............|..............|............|
c |..............|
4 segmente=136⇒c=34⇒b=102
2) Metoda algebrica
b:c=3⇒b=3c
3c+c=136
4c=136
c=34
b=102