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calculati 2a+3b+c in cazul in care a+b=17 si b+c=18

Răspuns :

Samsunggenius200
2a+3b+c=2a+3b+c a+b=17a+b+−b=17+−b
a=−b+17

b+c=18b+c+−c=18+−c
b=−c+18



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