Răspuns :
Eliminam parantezele efectuand inmultirile si obtinem:
[tex]3x+15-6x+12 = 4x+8-5x+20[/tex]
Separam necunoscuta:
[tex]3x-6x-4x+5x= 8+20-15-12[/tex]
Efectuam calculele si obtinem:
[tex]-2x= 1 |_{\cdot (-1)} \Longrightarrow\ 2x= - 1\ \Longrightarrow\ x=-\dfrac{1}{2}[/tex]
[tex]3x+15-6x+12 = 4x+8-5x+20[/tex]
Separam necunoscuta:
[tex]3x-6x-4x+5x= 8+20-15-12[/tex]
Efectuam calculele si obtinem:
[tex]-2x= 1 |_{\cdot (-1)} \Longrightarrow\ 2x= - 1\ \Longrightarrow\ x=-\dfrac{1}{2}[/tex]