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a fost răspuns

Efectuati :
(-2XYZ⁴)²
(1,5XYla a 3)la a 3


Răspuns :

[tex](-2XYZ ^{4} ) ^{2} =\ \textgreater \ (-2XYZ) ^{4*2} =\ \textgreater \ (-2XYZ) ^{6} [/tex] numere negative la puteri pozitive sunt numere pozitive =>[tex]( 2XYZ) ^{6} =\ \textgreater \ 2XYZ*2XYZ* 2XYZ*2XYZ*2XYZ*2XYZ=\ \textgreater \ [/tex][tex]=\ \textgreater \ 12X ^{6} Y ^{6} Z ^{6} [/tex]
[tex](1,5XY^{3} ) ^{3} =\ \textgreater \ (1,5XY) ^{3*3} =\ \textgreater \ (1,5XY) ^{9} =\ \textgreater \ [/tex][tex]1,5XY*1,5XY*1,5XY *1,5XY*1,5XY*1,5XY *1,5XY* [/tex][tex]1,5XY*1,5XY=\ \textgreater \ 13,5X^{9} Y ^{9} [/tex]