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a fost răspuns

x+2•x+3•x+...100•x-5049•x<44-3•13

Răspuns :

Zindrag
x(1+2+3+...+100 -5049)< 44-39
x(100*101/2-5048) < 5
(5050-5049)x< 5
x< 5
daca x ∈N⇒x∈{0,1,2,3,4}
daca x∈R⇒x∈(-∞,5)

O seara buna!
Creieros

x mai mic ca 5

1+2+3+100=106

5049-106= 4943
















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