👤
a fost răspuns

Rezolvati,in numere naturale,inecuatile:
a) 4*x-3(40-16) b) 1^2+2^2+3^2>2*x+6
c)674-10*x+3>sau egal cu 18*21-1
Va rog repde!

Răspuns :

a)4x-3(40-16)≤8⇔4x-3·24≤8⇔4x-72≤8⇔4x≤8+72⇔4x≤80⇔x≤80/4⇔x≤20
b)1²+2²+3²>2x+6⇔1+4+9>2x+6⇔14>2x+6⇔14-6>2x⇔8>2x⇔2x<8⇔x<8/2⇔x<4
c)674-10x+3≥18·21-1⇔677-10x≥378-1⇔677-10x≥377⇔677-377≥10x⇔300≥10x⇔10x≤300⇔x≤300/10⇔x≤30