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a fost răspuns

rezolvati in multimea numerelor naturale ecuatia:3x{10+2x[40-2x(28-3x5)]}-7X=51

Răspuns :

3×{10+2×[40-2×(28-15)]}-7x=51
3×{10+2×[40-2×13]}-7x=51
3×{10+2×[40-26]}-7x=51
3×{10+2×14}-7x=51
3×{10+28}-7x=51
3×38-7x=51
114-7x=51
7x=114-51
7x=63
x=63:7
x=9

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