Răspuns :
notam a,b,c,d cele 4 nr naturale consecutive
a=a
b=a+1
c=a+1+1=a+2
d=a+1+1+1=a+3
a+b+c+d= 114
a+a+1+a+2+a+3= 114
4a+6= 114
4a= 114-6
4a= 108
a= 108:4
a= 27
b= 27+1⇒b= 28
c= 27+2⇒ c= 29
d= 27+3 ⇒ d= 30
a=a
b=a+1
c=a+1+1=a+2
d=a+1+1+1=a+3
a+b+c+d= 114
a+a+1+a+2+a+3= 114
4a+6= 114
4a= 114-6
4a= 108
a= 108:4
a= 27
b= 27+1⇒b= 28
c= 27+2⇒ c= 29
d= 27+3 ⇒ d= 30
a+a+1+a+2+a+3=114 => 4a+6=114 => 4a=108 => a=27 =>a+1=28 => a+2=29 => a+3=30