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Cum se face ecuatia: 5x-12=3x-10+x^2-2\2 ?

Răspuns :

Dey2010
5x-12=3x-10+[tex] x^{2} [/tex] - 2/2 
5x-12=3x-10+[tex] x^{2} [/tex] - 1
-[tex] x^{2} [/tex] +5x-3x -12 + 10+1 = 0
-[tex] x^{2} [/tex] + 2x  -1 = 0

Δ= b² - 4ac
Δ= 4-4
Δ= 0

[tex] x_{1,2} [/tex] = [tex] \frac{-b}{2a} [/tex]
[tex] \frac{-2}{-2} =\ \textgreater \ x_{1,2} = 1[/tex]
5x-3x=2-10+x^2-1
2x-(x×x)=2-10-1
x[2-(1×1)]=-9
x=-9

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