[tex]10^{100}=2^{100} \cdot 5^{100}. \\ \\ Divizorii~naturali~ai~acestui~numar ~care~sunt~multipli~de~4~sunt~de\\ \\ forma~2^a \cdot 5^b,~unde~a,b\in N,~iar~a \geq 2. \\ \\ Deci~a \in \{2,3,4...,100\}~(99~de~valori)~si~b \in \{0,1,2,...,100 \}~(101~de~ \\ \\ valori).\\ \\ Conform~\underline{regulii~produsului},~exista~99 \cdot 101=9999~numere~cerute. [/tex]
