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Rares05
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cum se rezolva
(b+c)xa=50<
(b-c)xa=10
a=5
afla b si c

Răspuns :

Laura27
(b+c)×5=50=>b+c=10
(b-c)×5=10=> b-c=2=>b=c+2
c+2+c=10=>2c+2=10=>2c=8=>c=4=>c=6

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