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suma a 4 numere consecutive e 50,aflati numerele

Răspuns :

a
a+1
a+1+1
a+1+1+1
4a+6=50
4a=44
a=11
11,12,13,14
a+a+1+a+2+a+3=50
4a+6=50
4a=50-6
4a=44
a=44:4
a=11
11,12,13,14
Mult succes!!