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Andreutzakriss
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\sqrt{ \frac{x^2}{25} }- \sqrt{ \frac{y^2}{16} }=

Răspuns :

[tex]\sqrt{ \frac{x^2}{25} }- \sqrt{ \frac{y^2}{16} }= \\ \\ =\sqrt{ \frac{x^2}{5^2} }- \sqrt{ \frac{y^2}{4^2} }= \\ \\ =\sqrt{ (\frac{x}{5})^2 }- \sqrt{ (\frac{y}{4})^2 }= \\ \\ =\frac{x}{5}+ \frac{y}{4} = \frac{4x+5y}{20}[/tex]



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