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cate numere are sirul 2,5,8,11,...,299.

Răspuns :

   
[tex]\displaystyle n = \frac{299-2}{3}+1 = \frac{297}{3}+1 = 99+1= \boxed{100~de~termeni}[/tex]



Flavistin
[tex]2=3*0+2\\5=3*1+2\\8=3*2+2\\11=3*3+2\\......\\......\\......\\299=3*99+2\\Nr.terminilor:100[/tex]

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