Răspuns :
[tex]1) \\ 25 = 5^2 = pp \\ 1 = 1^2 = pp \\ 9 \ \textless \ 14 \ \textless \ 16 ~~=\ \textgreater \ 14 \neq pp~\text{deoarece este intre 2 patrate consecutive} \\ 0 = 0^2 = pp\\ 9 \ \textless \ 12 \ \textless \ 16 ~~=\ \textgreater \ 12 \neq pp~\text{deoarece este intre 2 patrate consecutive} \\ 36 \ \textless \ 48 \ \textless \ 49 ~~=\ \textgreater \ 49 \neq pp~\text{deoarece este intre 2 patrate consecutive} \\ 121 = 11^2 = pp \\ 256\ \textless \ 257\ \textless \ 289 \\ ~~=\ \textgreater \ 257 \neq pp~\text{deoarece este intre 2 patrate perfecte consecutive} [/tex]
[tex]2) \\ a)~~ \sqrt{81} = 9 ~~Adevarat \\ b)~~ \sqrt{7^2}=7 ~~Adevarat \\ c)~~ \sqrt{(-7)^2}=7 ~~Adevarat \\ d)~~ \sqrt{11^2}=111 ~~Gresit.~~~~Corect ~este: \sqrt{11^2}=11~~nu~111 \\ e)~~ \sqrt{(-314)^2}=314 ~~Adevarat [/tex]
[tex]2) \\ a)~~ \sqrt{81} = 9 ~~Adevarat \\ b)~~ \sqrt{7^2}=7 ~~Adevarat \\ c)~~ \sqrt{(-7)^2}=7 ~~Adevarat \\ d)~~ \sqrt{11^2}=111 ~~Gresit.~~~~Corect ~este: \sqrt{11^2}=11~~nu~111 \\ e)~~ \sqrt{(-314)^2}=314 ~~Adevarat [/tex]
