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80-2*acolada135:9+15:3*paranteza patrata265-(18:9+2)*65inchidem paranteza patrata si acolada=?

Răspuns :

Cristinabranzan13
80-2x{135:9+15:3x[265-(18:9+2)x65]}=
80-2x{135:9+15:3x[265-(2+2)x65]}=
80-2x{135:9+15:3x[265-4x65]}=
80-2x{135:9+15:3x[265-260]}=
80-2x{135:9+15:3x5]}=
80-2x{15+25}=
80-2x40=
=80-80
=0

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