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a fost răspuns

Descompuneti in factori: (x+1)×(x+3)2 - 4(x+1)
Unde am pus 2 dupa paranteza inseamna ca e la puterea a 2a

Răspuns :

[tex](x+1)*(x+3)^2-4(x+1)=\\ (x+1)[(x+3)^2-4]=\\ (x+1)(x^2+6x+9-4)=\\ (x+1)(x^2+6x+5)=\\ (x+1)(x^2+5x+x+5)=\\ (x+1)[x(x+5)+(x+5)]=\\ (x+1)(x+5)(x+1)=(x+5)*(x+1)^2[/tex]

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