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Alinboss388
a fost răspuns

Calculati :
a)2 la puterea 3 la puterea 2 : (2 la puterea 2) la puterea 3
b)3 la puterea 2 la puterea 5 : 3 la puterea 5 la puterea 2
c) (4+2 la puterea 192:2 la puterea 188):5
d) (1+2*2 la puterea 2*2 la puterea 4) : (2 la puterea 7+1)
e) [(3 la puterea 3) la puterea 12:3 la puterea 2 la puterea 5 -56]:5
f) 8 la puterea 16 : (2*2 la puterea 4 * 2 la puterea 10) la puterea 3 -2 la puterea 1 - 2 la puterea 0

Răspuns :

[tex]a) (2^3)^2:(2^2)^3=2^6:2^6=2^0=1\\ b) (3^2)^5:(3^5)^2=3^{10}:3^{10}=3^0=1\\ c) (4+2^{192}:2^{188}):5=(4+2^4):5=(4+16):5=20:5=4\\ d) (1+2*2^2*2^4):(2^7+1)=(1+2^7):(2^7+1)=1\\ e) [(3^3)^{12}:(3^2)^5-56]:5=[3^{36}:3^{10}-56]:5=[3^{26}-56]:5=???\\ f) 8^{16}:(2*2^4*2^{10})^3-2^1-2^0=(2^3)^{16}:(2^{15})^3-2-1=2^{48}:2^{30}-3\\=2^{18}-3=262144-3=262141\\ [/tex]

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