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a fost răspuns

7la putera 2 :{17la puterea 2:289+2*[(2 la puterea 3*3)la puterea 15:(2*2la puterea 43*3 la puterea 15)+1 la puterea 50]}=(ORDINE EFECTUARII OPERATIILOR VA ROG)

Răspuns :

7^2÷{17^2÷289+2[(2^3×3)^15÷(2×2^43×3^15)+1^50}]=
7^2÷{17^2÷289+2×[(2^45×3^15)÷(2^44×3^15)+1]=
7^2÷[17^2÷289+2×(2^1×3^0)+2]=7^2÷(17^2÷289+2×2+2)=7^2÷(17^2÷289+4+2)=
7^2÷(17^2÷17^2+4+2)=
7^2÷(1+4+2)=7^2÷7=7^2-7^1=7