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aflati cel mai mare numar natural la care daca impartim pe 132 , 160, 230 obtinem respectiv resturile 12 10 20 urgent

Răspuns :

Yenp
132-12=120
160-10=150
230-20=210
120=10×3×2^2
150=10×3×5
210=10×3×7
cmmdc=10×3×5×7×2^2=4200
4200÷132=35rest12
4200÷160=28rest10
4200÷230=20rest20

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