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Aflati cel mai mic numar natural care inpartit la 6,14,18 da restul 3,11 ,15

Răspuns :

AditzaPetre
6:x=c1 rest 3 => x=6c1+3 /+3 => x+3=6(c1+1) 14:x=c2 rest 11=>x=14c2+11 /+3=> x+3=14(c2+1) 18:x=c3 rest 15=> x=18c3 +15 /+3=> x+3=18(c3+1) . x+3=[6,14,18] =126 x=123
Alitta
numarul minim cautat = n ;
=> n=M₆+3     | +3  =>  n+3=M₆
     n=M₁₄+11  | +3  =>   n+3=M₁₄
     n=M₁₈+15  | +3  =>   n+3=M₁₈
                      => n+3 = [6;14;18]=126  =>  n=126-3=123 .

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