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daca (2×9)35=235×3a ,atunci determinati valoarea numarului natural a

Răspuns :

Renatemambouko
(2×9)35=235×3a
18×35=235×3a
630=705a
a=630/705=126/141=42/47
GabiPuneIntrebari
(2x9)35=235x3a
18x35=235x3a
630=235x3a
[tex] \frac{630}{3} [/tex]=235a
210=235a
a=[tex] \frac{235}{210} [/tex]
a=[tex] \frac{47}{42} [/tex]

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