A
CH2=CH-CH3 + Cl2= CHCl=CH-CH3 +HCl
B
CH2=CH-CH3 + Cl2= CH2Cl-CHCl-CH3
CH2=CH-CH3 ------>NETRANSFORMAT
nA/nB=15/1
DIn conversia utila rezulta : 1oo moli propena se transforma in 90 moli clorura(A)
Din raportul de moli rezulta 15/1=90/moliB---> nB=6 moli
Raman netransformati; 100-90-6--->4moli
Ct=96x100/100---> 96% sper sa fie bine !