Răspuns :
I- primul termen
II- al doilea termen
III- al treilea termen
I-1250
II- 1250-760= 490
III- 490+950= 1440
I+II+III= 1250+490+1440=3180
II- al doilea termen
III- al treilea termen
I-1250
II- 1250-760= 490
III- 490+950= 1440
I+II+III= 1250+490+1440=3180
a= 1.250
b= 1.250-760= 490
c= 490+950=1.440
a+b+c= 1.250+490+1.440
a+b+c= 3.180
b= 1.250-760= 490
c= 490+950=1.440
a+b+c= 1.250+490+1.440
a+b+c= 3.180