Răspuns :
[tex]\displaystyle 1+3+5+7+...+101 \\ 101=1+(n-1) \cdot 2 \\ 101=1+2n-2 \\ 2n=101-1+2 \\ 2n=102 \\ n=102:2 \\ n=51 \\ S_{51}= \frac{2+50 \cdot 2}{2} \cdot 51 \\ \\ S_{51}= \frac{2+100}{2} \cdot 51 \\ \\ S_{51}= \frac{102}{2} \cdot 51 \\ \\ S_{51}= 51 \cdot 51 \\ S_{51}=51^2-p.p[/tex]
S=1+3+5+...+(2n-1)=n^2 => A=1+3+5+...+101
=1+3+5+...+(2•51-1)
=51^2
=1+3+5+...+(2•51-1)
=51^2
