👤
Ancut
a fost răspuns

a)([tex] 2x^{2}+4xy) + ( y^{2} - 2xy) - ( x^{2} + 4 y^{2} - 5xy) + ( x^{2} - y^{2})=[/tex]
b)[tex]11m+(3n-5m+6)-(4m-2n-8)=[/tex]
c)[tex](12 m^{2}-5m+ n^{2})-(2 n^{2}+6m-3 m^{2})-(12 m^{2} - mn)=[/tex]


Răspuns :

[tex]a)2x^2+4xy+y^2-2xy-x^2-4y^2+5xy+x^2-y^2=2x^2+7xy-4y^2\\ b)11m+3n-5m+6-4m+2n+8=2m+5n+14\\ c)12m^2-5m+n^2-2n^2-6m+3m^2-12m^2+mn=\\ =3m^2-11m-n^2+mn[/tex]