CaCO₃ → CaO + CO₂↑
a) masa pura CaCO₃ = Md
Md = Ms*c/100
Md = 400*90/100
Md = 360 g CaCO₃
b) M CaCO₃= 40+12+48 = 100 g/mol
M CO₂= 12+32= 44 g/mol
100/360=44/x
x= 360*44/100
x= 15840/100
x= 158, 4 g CO₂
1 mol CO₂...... 44 g
x moli CO₂......158,4 g
1/x = 44/158,4
x= 158,4/44
x= 3,6 moli CO₂
1 mol CO₂...... 22,4 l
3,6 moli CO₂..... x l
1/3,6 = 22,4/x
x= 3,6* 22,4
x= 80,64 litri CO₂ (volumul)
