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Deea82002
a fost răspuns

[2,5+0,1(6)+0,(3)]×[tex](1- \frac{1}{3} ) ^{2} [/tex]

Răspuns :

CarMina03
[2,5+0,1(6)+0,(3)]×(1-1/3)²=[15/10+15/90+3/9]×(1-1/3)²=[3/2+1/18+1/3]×(1-1/3)²=[27/18+1/18+6/18]×(3/3-1/3)²=34/18×(2/3)²=17/9x4/9=68/91 




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