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Ajutati-ma!Rezolvati: (√1+√2)(√1 +√3)•[√50:5 +3° +(1 /√3)•3]totul la puterea 2-a!Va rog!Dau coroana!

Răspuns :

Renatemambouko
(√1+√2)(√1 +√3)•[√50:5 +3° +(1 /√3)•3]²=
=(1+√2)(1 +√3)•[√2 +1 +√3]²=
=(1+√2+√3+√6)(√2 +1 +√3)(√2 +1 +√3)=
=(1+√2+√3+√6)(2+√2+√6+√2 +1 +√3+√6+√3+3)=
=(1+√2+√3+√6)(6+2√2+2√6+2√3)=
=6+6√2+6√3+6√6+2√2+8+2√6+2√12+2√6+2√12+2√18+12+2√3+2√6+6+2√18=
=6+6√2+6√3+6√6+2√2+8+2√6+4√3+2√6+4√3+6√2+12+2√3+2√6+6+6√2=
=32+20√2+16√3+12√6









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