👤
a fost răspuns

76. Rezolvati in multimea numerelor reale inecuatia -1≤[tex] \frac{x+1}{3} [/tex]<2.

Răspuns :

Miky93
[tex]-1 \leq \frac{x+1}{3} < 2 \ \ aducem \ la \ acelasi \ numitor \\\\ -3 \leq x+1 < 6 \ \ |(-1) \\ \\ -4 \leq x < 5 \\ \\ => \boxed{x = [-4;5) }[/tex]
SmartGuy
-1≤[tex] \frac{x+1}{3}[/tex]<2|(*3)
-3≤x+1<6 |(-1)
-4≤x<5
x∈ [-4,5)

Alte intrebari