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calculati: fractii
a)(3^7ori5^12)^2
b)(2^10ori3^7)9:(2^5ori3^6)^10
c)(4+3)^3-(4-3)^10
d)(10^3-125ori2^3):123^123
e)[(10^3:5^2:8+3^2ori5^2):3^0]ori2^2^2
f){[(12^2+5^2):13]^2-2^7-2^0}:2^3

Răspuns :

Renatemambouko
a)(3^7×5^12)^2=3^14×5^24
b)(2^10×3^7)^9:(2^5×3^6)^10=2^90× 3^63 :2^50×3^60=2^40×3^3
c)(4+3)^3-(4-3)^10=7^3-1^10=343-1=342
 d)(10^3-125×2^3):123^123=(2^3×5^3-5^3×2^3):123^123=0:123^123=0
 e)[(10^3:5^2:8+3^2×5^2):3^0]×2^2^2=[(2^3×5^3:5^2:2^3+3^2×5^2):1]×2^4=
=(5:1)×2^4=5*16=80
 f){[(12^2+5^2):13]^2-2^7-2^0}:2^3 ={[(144+25):13]^2-2^7-1}:2^3 =
={[(169:13]^2-2^7-1}:2^3 =(13^2-2^7-1):2^3 =169-128-1=40:2^3=5×2^3:2^3=5











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