Elimin excesul; 465,25- 0,20x465,25=>465,25-91,25=>365g Cl2 necesar in reactia
2moli 2moli
2Fe + 3Cl2 = 2FeCl3
3x71gCl2 2x(56+3x35,5)gFeCl3
365 x x este ,rotunjit , 560g dar veriflca !
Aceasta masa se dizolva in apa si se obtine sol. 70% ; se calc. m,sol
c%=m,dizx1oo/.m,sol 70/100= 560/ m,sol, unde m,sol=m,diz+m,apa
m,sol=800g m,apa=800-560g