Răspuns :
a+b=27
a=4 ×b
5
4 ×b+b=27 (aducem la acelasi numitor)
5
4b+5b =27⇒9b =27⇒9b=27×5⇒b=135÷9⇒b=15
5 5
a=4 ×b⇒a=4×15 ⇒a=4×3⇒a=12 (simplificam 15 cu 5 si ne da 3)
5 5
verificare:
4 ×15+15=27⇒12+15=27 A
5
a=4 ×b
5
4 ×b+b=27 (aducem la acelasi numitor)
5
4b+5b =27⇒9b =27⇒9b=27×5⇒b=135÷9⇒b=15
5 5
a=4 ×b⇒a=4×15 ⇒a=4×3⇒a=12 (simplificam 15 cu 5 si ne da 3)
5 5
verificare:
4 ×15+15=27⇒12+15=27 A
5
a+b=27
a=4 ×b
5
4 ×b+b=27 (aducem la acelasi numitor)
5
4b+5b =27⇒9b =27⇒9b=27×5⇒b=135÷9⇒b=15
5 5
a=4 ×b⇒a=4×15 ⇒a=4×3⇒a=12 (simplificam 15 cu 5 si ne da 3)
5 5
verificare:
4 ×15+15=27⇒12+15=27 A
5
a=4 ×b
5
4 ×b+b=27 (aducem la acelasi numitor)
5
4b+5b =27⇒9b =27⇒9b=27×5⇒b=135÷9⇒b=15
5 5
a=4 ×b⇒a=4×15 ⇒a=4×3⇒a=12 (simplificam 15 cu 5 si ne da 3)
5 5
verificare:
4 ×15+15=27⇒12+15=27 A
5