[tex]\displaystyle
0,16x^2+0,8x+y^2-2y+2=0 \\
0,16x^2+0,8x+y^2-2y+1+1=0 \\
(0,16x^2+0,8x+1)+(y^2-2y+1)=0 \\
((0,4x)^2+2 \cdot 0,4x \cdot 1+1^2)+(y^2+2 \cdot y \cdot (-1)+(-1)^2)=0 \\
(0,4x+1)^2+(y -1)^2=0 \\ \\
0,4x+1=0 ~~\Longrightarrow~~x = \frac{-1}{0,4} = - \frac{10}{4}= \boxed{- \frac{5}{2}}~~~(radacina ~~dubla ) \\ \\
y-1 = 0 ~~\Longrightarrow~~ y=\boxed{1}~~~(radacina ~~dubla )[/tex]
