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Iancudiana28
a fost răspuns

Calculati:
a) √48-√18-√108+√128
b)√162-√75-√32+√142
c)√18(√96-√192-√216+√432)
d)√12(-√108-√150+√243+√384)

Răspuns :

a) √48-√18-√108+√128=4√3-3√2-6√3+8√2=5√2-2√3

b) √162-√75-√32+√142=9√2-5√3-4√2+√142=5√2-5√3+√142

c) √18(√96-√192-√216+√432)=3√2(4√6-8√3-6√6+12√3)=3√2(4√3-2√6)=12√6-12√3

d) √12(-√108-√150+√243+√384)=2√3(-6√3-5√6+9√3+8√6)=2√3(3√3+3√6)=18+18√2

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