Răspuns :
a.) a+b+c=1000.
a-50/100a=1/2a
b-2/3b=1/3b
c-80/100c=1/5c
am si simplificat unde s-a putut.
sumele ramase sunt egale
1/2a=1/3b=1/5c
si putem scoate b si c in functie de a
b=3a/2
c=5a/2
inlocuim in prima ecuatie
a+3a/2+5a/2=1000 si rezolvam
10a/2=1000
a=200
b=300
c=500
b.) a a cheltuit - 50/100*200=100
b a cheltuit - 2/3*300=200
c a cheltuit - 80/100*500=400
c.) b/a+b+c=300/1000=30%.
succes.
a-50/100a=1/2a
b-2/3b=1/3b
c-80/100c=1/5c
am si simplificat unde s-a putut.
sumele ramase sunt egale
1/2a=1/3b=1/5c
si putem scoate b si c in functie de a
b=3a/2
c=5a/2
inlocuim in prima ecuatie
a+3a/2+5a/2=1000 si rezolvam
10a/2=1000
a=200
b=300
c=500
b.) a a cheltuit - 50/100*200=100
b a cheltuit - 2/3*300=200
c a cheltuit - 80/100*500=400
c.) b/a+b+c=300/1000=30%.
succes.
a+b+c=1000
50% din a= 50/100 * a= 1/2 * a= a/2 -a cheltuit primul
a-a/2= (2a-a)/2= a/2 i-a ramas primului
2/3 din b= 2/3 * b= 2b/3 -a cheltuit al doilea
b-2b/3= (3b-2b)/3= b/3 -i-a ramas celui de-al 2-lea
80% din c= 80/100 * c= 8/10 * c= 4/5 * c= 4c/5 -a cheltuit al 3-lea
c-4c/5= (5c-4c)/5= c/5 - i-a ramas celui de-al 3-lea
a/2 = b/3 =c/5=k
a=2k
b=3k
c=5k
2k+3k+5k=1000
10k=1000
k=100
a)a=2*100=200
b=3*100=300
c=5*100=500
b)a=200/2=100
b=2*300/3=2*100=200
c=4*500/5=4*100 =400 lei a cheltuit fiecare elev
c)p% din 1000=300
p/100 *1000=300
p*10=300
p=30%
50% din a= 50/100 * a= 1/2 * a= a/2 -a cheltuit primul
a-a/2= (2a-a)/2= a/2 i-a ramas primului
2/3 din b= 2/3 * b= 2b/3 -a cheltuit al doilea
b-2b/3= (3b-2b)/3= b/3 -i-a ramas celui de-al 2-lea
80% din c= 80/100 * c= 8/10 * c= 4/5 * c= 4c/5 -a cheltuit al 3-lea
c-4c/5= (5c-4c)/5= c/5 - i-a ramas celui de-al 3-lea
a/2 = b/3 =c/5=k
a=2k
b=3k
c=5k
2k+3k+5k=1000
10k=1000
k=100
a)a=2*100=200
b=3*100=300
c=5*100=500
b)a=200/2=100
b=2*300/3=2*100=200
c=4*500/5=4*100 =400 lei a cheltuit fiecare elev
c)p% din 1000=300
p/100 *1000=300
p*10=300
p=30%