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Paula222
a fost răspuns

Daca 2·a+b=5 si 2·b+3·c=7, calculati 4·a+8·b+9·c

Răspuns :

Ctinamaria31xxx
2·a+b=5 |*2 =>
4a+2b=10

2·b+3·c=7 |*3
6b+9c=21
calculati 4·a+8·b+9·c ( am descompus 8b sa 2b+6b)

4a+2b+6b+9c=
10+21=31
Miky93
2a+b=5

2b+3c=7

4a+6b+9c =2(2a+b)+3(2b+3c)=  2*5+3*7=  10+21=31

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