Răspuns :
A=2003+2*(2002*2003)/2
A= 2003+2002*2003
= 2003(1+2002)
= 2003*2003=2003^2 deci e pătrat perfect
A= 2003+2002*2003
= 2003(1+2002)
= 2003*2003=2003^2 deci e pătrat perfect
[tex]A= 2003 + 2* [ (1+2002)*2002 ] /2 =2003 + 2003 * 2002 = \\ \\ = 2003 ( 1+2002) = 2003 *2003 = 2003^{2}-----patrat.perfect [/tex]