👤
Paulinablajan
a fost răspuns

daca x+2y=17 si y-3z=4 atunci calculati
x+3y-3z 2x+5y-3z (3x+6y)+(2y-6z) (2x+4y)*(x+4y-6z

Răspuns :

Dixie
x+2y=17
y-3z=4
(x+2y)+(y-3z)=x+3y-3z=17+4=21
(x+3y-3z)+(x+2y)=2x+5y-3z=21+17=38
(3x+6y)+(2y-6z)=3x+8y-6z=2x+5y-3z+(x+2y)+(y-3z)=38+17+4=59
(2x+4y)(x+4y-6z)=[2*(x+2y)][(x+2y)+2(y-3z)]=2*17*(17+2*4)=2*17*25=850