-3 < 1 - 2x < 11 scadem 1
- 3 -1 < -2x < 11 - 1 ; -4 < - 2x < 10 impartim cu ( -2) DAR :
10 / ( - 2 ) < x < - 4 / ( -2) ⇒ - 5 < x < 2
A = ( - 5 ; 2)
A П N = { 0 ; 1 }
1 /2 ≤ ( x +2) / 6 ≤ 5 /3 numitor 6
3 ≤ x + 2 ≤ 5 · 2
3 - 2 ≤ x +2 - 2 ≤ 10 - 2
1 ≤ x ≤ 8 interval , B = [ 1 ; 8 ]